![]() The indexOf () method returns -1 if the value is not found. Looking at the console log it seems like the length of repeatLater is one plus the number of objects which is odd, the addition being proto. Definition and Usage The indexOf () method returns the position of the first occurrence of a value in a string. ![]() I suspect that the problem might be because there are objects/entries in the repeatLater array that do not have the ‘minTrial’ key. The findIndex() method in JavaScript is used to search an array for an element that matches a specific condition, and returns the index of the first element. Occasionally I get thrown this error : TypeError: Cannot read property ‘minTrial’ of undefined repeatIdx = repeatLater.findIndex( x => x.minTrial <= trials.thisN ) Here is the method's syntax: 1 array. It iterates through each element of the array and calls the provided testing function with each element. Javascript is required to design the behaviour of the web pages. The findIndex () method finds the index of the first element in an array that satisfies the testing function. After retrieving the trial, I delete that object from the array. Javascript(JS) is a object-oriented programming language which adhere to ECMA Script Standards. ![]() repeatLater.push() Īt the beginning of the routine, I am using findIndex to search through repeatLater to find the index of the first instance where the my specifications are met, in this case I want the trial number to be at least the minTrial. I created an array of objects (named repeatLater) where each object consists of specifications of a that I’d want to repeat after a number of trials. Hi all, This is more of a javascript question. ![]()
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